What are the solutions to the equation n^2=-3n ?

The solutions to the equation n^2=-3n are n=0,n=-3

Find the zeros of n^2=-3n

The zeros of n^2=-3n are n=0,n=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} = - 3 n

n = 0, n = - 3

Solution steps

n^{2} = - 3 n

Move

3 n

to the left side

n^{2} + 3 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 0 = 3

n_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 3}{2 \cdot 1}, n_{2} = \frac{- 3 - 3}{2 \cdot 1}

n = \frac{- 3 + 3}{2 \cdot 1} : 0

n = \frac{- 3 - 3}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

n = 0, n = - 3

\frac{1}{4} (x + 2)^{2} - 2 = 3

2 \cdot x^{2} + x = 15

4 y - 20 y^{2} = 0

y, x - y^{2} = 1

7 x - 3 + 8 x^{2} = 7 + 4 x^{2} - x

What are the solutions to the equation n^2=-3n ?
The solutions to the equation n^2=-3n are n=0,n=-3
Find the zeros of n^2=-3n
The zeros of n^2=-3n are n=0,n=-3