What are the solutions to the equation -8x^2+10x+25=0 ?

The solutions to the equation -8x^2+10x+25=0 are x=-5/4 ,x= 5/2

Find the zeros of -8x^2+10x+25=0

The zeros of -8x^2+10x+25=0 are x=-5/4 ,x= 5/2

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- 8 x^{2} + 10 x + 25 = 0

x = - \frac{5}{4}, x = \frac{5}{2}

Solution steps

- 8 x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 8 ) \cdot 25}{2 ( - 8 )}

1 0^{2} - 4 (- 8) \cdot 25 = 30

x_{1, 2} = \frac{- 10 \pm 30}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 10 + 30}{2 ( - 8 )}, x_{2} = \frac{- 10 - 30}{2 ( - 8 )}

x = \frac{- 10 + 30}{2 ( - 8 )} : - \frac{5}{4}

x = \frac{- 10 - 30}{2 ( - 8 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = \frac{5}{2}

x (x - 10) + 21 = 0

6 x^{2} - 3 x = 0

7 x^{2} - 15 x + 8 = 0

2 t (t + 1) = 7

r, y = 4 π r^{2}

What are the solutions to the equation -8x^2+10x+25=0 ?
The solutions to the equation -8x^2+10x+25=0 are x=-5/4 ,x= 5/2
Find the zeros of -8x^2+10x+25=0
The zeros of -8x^2+10x+25=0 are x=-5/4 ,x= 5/2