What are the solutions to the equation x^2-40x+1200=0 ?

The solutions to the equation x^2-40x+1200=0 are x=20+20sqrt(2)i,x=20-20sqrt(2)i

Find the zeros of x^2-40x+1200=0

The zeros of x^2-40x+1200=0 are x=20+20sqrt(2)i,x=20-20sqrt(2)i

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x^{2} - 40 x + 1200 = 0

x = 20 + 202 i, x = 20 - 202 i

Solution steps

x^{2} - 40 x + 1200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot 1200}{2 \cdot 1}

Simplify

(- 40)^{2} - 4 \cdot 1 \cdot 1200 : 402 i

x_{1, 2} = \frac{- ( - 40 ) \pm 40 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 40 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 40 ) - 40 2 i}{2 \cdot 1}

x = \frac{- ( - 40 ) + 40 2 i}{2 \cdot 1} : 20 + 202 i

x = \frac{- ( - 40 ) - 40 2 i}{2 \cdot 1} : 20 - 202 i

The solutions to the quadratic equation are:

x = 20 + 202 i, x = 20 - 202 i

(2 x + 4) (x - 7) = 2 (5 x - 3)

x, 0 = 2 x^{2} + y^{2}

15 x^{2} - 9 x + 12 = 0

5 x^{2} + 11 x - 1 = 0

x^{2} + 4 x = 0

What are the solutions to the equation x^2-40x+1200=0 ?
The solutions to the equation x^2-40x+1200=0 are x=20+20sqrt(2)i,x=20-20sqrt(2)i
Find the zeros of x^2-40x+1200=0
The zeros of x^2-40x+1200=0 are x=20+20sqrt(2)i,x=20-20sqrt(2)i