What are the solutions to the equation solvefor x,0=2x^2+y^2 ?

The solutions to the equation solvefor x,0=2x^2+y^2 are x=i(sqrt(2)y)/2 ,x=-i(sqrt(2)y)/2

Find the zeros of solvefor x,0=2x^2+y^2

The zeros of solvefor x,0=2x^2+y^2 are x=i(sqrt(2)y)/2 ,x=-i(sqrt(2)y)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, 0 = 2 x^{2} + y^{2}

x = i \frac{2 y}{2}, x = - i \frac{2 y}{2}

Solution steps

0 = 2 x^{2} + y^{2}

Switch sides

2 x^{2} + y^{2} = 0

Move

y^{2}

to the right side

2 x^{2} = - y^{2}

Divide both sides by

2

x^{2} = - \frac{y ^{2}}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{y ^{2}}{2}, x = - - \frac{y ^{2}}{2}

Simplify

- \frac{y ^{2}}{2} : i \frac{2 y}{2}

Simplify

- - \frac{y ^{2}}{2} : - i \frac{2 y}{2}

x = i \frac{2 y}{2}, x = - i \frac{2 y}{2}

15 x^{2} - 9 x + 12 = 0

5 x^{2} + 11 x - 1 = 0

x^{2} + 4 x = 0

- x^{2} + 8 x - 5

x^{2} + 22 x - 5 = 0

What are the solutions to the equation solvefor x,0=2x^2+y^2 ?
The solutions to the equation solvefor x,0=2x^2+y^2 are x=i(sqrt(2)y)/2 ,x=-i(sqrt(2)y)/2
Find the zeros of solvefor x,0=2x^2+y^2
The zeros of solvefor x,0=2x^2+y^2 are x=i(sqrt(2)y)/2 ,x=-i(sqrt(2)y)/2