What are the solutions to the equation 15+26d=-8d^2 ?

The solutions to the equation 15+26d=-8d^2 are d=-5/2 ,d=-3/4

Find the zeros of 15+26d=-8d^2

The zeros of 15+26d=-8d^2 are d=-5/2 ,d=-3/4

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15 + 26 d = - 8 d^{2}

d = - \frac{5}{2}, d = - \frac{3}{4}

Decimal Notation

d = - 2.5, d = - 0.75

Solution steps

15 + 26 d = - 8 d^{2}

Switch sides

- 8 d^{2} = 15 + 26 d

Move

26 d

to the left side

- 8 d^{2} - 26 d = 15

Move

15

to the left side

- 8 d^{2} - 26 d - 15 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 ( - 8 ) ( - 15 )}{2 ( - 8 )}

(- 26)^{2} - 4 (- 8) (- 15) = 14

d_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 ( - 8 )}

Separate the solutions

d_{1} = \frac{- ( - 26 ) + 14}{2 ( - 8 )}, d_{2} = \frac{- ( - 26 ) - 14}{2 ( - 8 )}

d = \frac{- ( - 26 ) + 14}{2 ( - 8 )} : - \frac{5}{2}

d = \frac{- ( - 26 ) - 14}{2 ( - 8 )} : - \frac{3}{4}

The solutions to the quadratic equation are:

d = - \frac{5}{2}, d = - \frac{3}{4}

y^{2} - 9 y = - 14

w^{2} - 4 = 12

5 p^{2} + 11 p + 6 = 0

(2 x + 4) (x - 3) = 0

7 x^{2} - x^{2} = 168

What are the solutions to the equation 15+26d=-8d^2 ?
The solutions to the equation 15+26d=-8d^2 are d=-5/2 ,d=-3/4
Find the zeros of 15+26d=-8d^2
The zeros of 15+26d=-8d^2 are d=-5/2 ,d=-3/4