What are the solutions to the equation y^2-9y=-14 ?

The solutions to the equation y^2-9y=-14 are y=7,y=2

Find the zeros of y^2-9y=-14

The zeros of y^2-9y=-14 are y=7,y=2

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y^{2} - 9 y = - 14

y = 7, y = 2

Solution steps

y^{2} - 9 y = - 14

Move

14

to the left side

y^{2} - 9 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

y_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, y_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

y = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

y = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 7, y = 2

w^{2} - 4 = 12

5 p^{2} + 11 p + 6 = 0

(2 x + 4) (x - 3) = 0

7 x^{2} - x^{2} = 168

x^{2} + 10 x = 2

What are the solutions to the equation y^2-9y=-14 ?
The solutions to the equation y^2-9y=-14 are y=7,y=2
Find the zeros of y^2-9y=-14
The zeros of y^2-9y=-14 are y=7,y=2