What is the answer to 2^{3-x}=5^x ?

The answer to 2^{3-x}=5^x is x=(3ln(2))/(ln(10))

Solve for x: 2^{3-x}=5^x

The solution is x=(3ln(2))/(ln(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{3 - x} = 5^{x}

x = \frac{3 ln ( 2 )}{ln ( 10 )}

Solution steps

2^{3 - x} = 5^{x}

Apply exponent rules

(3 - x) ln (2) = x ln (5)

Solve

(3 - x) ln (2) = x ln (5) : x = \frac{3 ln ( 2 )}{ln ( 10 )}

x = \frac{3 ln ( 2 )}{ln ( 10 )}

2^{x} \cdot 5^{x - 1} = 0.01

800 = 25 (2^{t})

2^{x + 2} + 2^{x - 1} - 2^{x - 3} = 70

n, p = \frac{1}{1 0 ^{n}}

2^{2 x + 18} = 3^{x - 12}

What is the answer to 2^{3-x}=5^x ?
The answer to 2^{3-x}=5^x is x=(3ln(2))/(ln(10))
Solve for x: 2^{3-x}=5^x
The solution is x=(3ln(2))/(ln(10))