What are the solutions to the equation -2x(x+2)(x^2-15)=0 ?

The solutions to the equation -2x(x+2)(x^2-15)=0 are x=0,x=-2,x=-sqrt(15),x=sqrt(15)

Find the zeros of -2x(x+2)(x^2-15)=0

The zeros of -2x(x+2)(x^2-15)=0 are x=0,x=-2,x=-sqrt(15),x=sqrt(15)

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- 2 x (x + 2) (x^{2} - 15) = 0

x = 0, x = - 2, x = - 15, x = 15

Decimal Notation

x = 0, x = - 2, x = - 3.87298 \dots, x = 3.87298 \dots

Solution steps

- 2 x (x + 2) (x^{2} - 15) = 0

Factor

- 2 x (x + 2) (x^{2} - 15) : - 2 x (x + 2) (x + 15) (x - 15)

- 2 x (x + 2) (x + 15) (x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 2 = 0 or x + 15 = 0 or x - 15 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 15 = 0 : x = - 15

Solve

x - 15 = 0 : x = 15

The solutions are

x = 0, x = - 2, x = - 15, x = 15

5 x^{3} + 4 x^{2} + 6 x + 2 = 0

x^{3} - 2 x^{2} - 19 x + 20 = 0

x^{3} - 4 x^{2} = 21 x

x^{3} - 5 x^{2} + 9 x - 5 = 0

- x^{3} + 7 x^{2} - 16 x + 12 = 0

What are the solutions to the equation -2x(x+2)(x^2-15)=0 ?
The solutions to the equation -2x(x+2)(x^2-15)=0 are x=0,x=-2,x=-sqrt(15),x=sqrt(15)
Find the zeros of -2x(x+2)(x^2-15)=0
The zeros of -2x(x+2)(x^2-15)=0 are x=0,x=-2,x=-sqrt(15),x=sqrt(15)