What are the solutions to the equation x^3-2x^2-19x+20=0 ?

The solutions to the equation x^3-2x^2-19x+20=0 are x=1,x=-4,x=5

Find the zeros of x^3-2x^2-19x+20=0

The zeros of x^3-2x^2-19x+20=0 are x=1,x=-4,x=5

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x^{3} - 2 x^{2} - 19 x + 20 = 0

x = 1, x = - 4, x = 5

Solution steps

x^{3} - 2 x^{2} - 19 x + 20 = 0

Factor

x^{3} - 2 x^{2} - 19 x + 20 : (x - 1) (x + 4) (x - 5)

(x - 1) (x + 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 4 = 0 or x - 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 4 = 0 : x = - 4

Solve

x - 5 = 0 : x = 5

The solutions are

x = 1, x = - 4, x = 5

x^{3} - 4 x^{2} = 21 x

x^{3} - 5 x^{2} + 9 x - 5 = 0

- x^{3} + 7 x^{2} - 16 x + 12 = 0

y^{3} = - 1

y^{3} = - 8

What are the solutions to the equation x^3-2x^2-19x+20=0 ?
The solutions to the equation x^3-2x^2-19x+20=0 are x=1,x=-4,x=5
Find the zeros of x^3-2x^2-19x+20=0
The zeros of x^3-2x^2-19x+20=0 are x=1,x=-4,x=5