What is the answer to 2log_{4}(x+1)=log_{4}(11-x) ?

The answer to 2log_{4}(x+1)=log_{4}(11-x) is x=2

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2log_{4}(x+1)=log_{4}(11-x)

2 lo g_{4} (x + 1) = lo g_{4} (11 - x)

x = 2

Solution steps

2 lo g_{4} (x + 1) = lo g_{4} (11 - x)

Apply log rules

(x + 1)^{2} = 11 - x

Solve

(x + 1)^{2} = 11 - x : x = 2, x = - 5

x = 2, x = - 5

Verify Solutions:

x = 2

True

, x = - 5

False

The solution is

x = 2

lo g_{2} (x + 7) = 3 - lo g_{2} (x + 5)

ln (x^{2}) + ln (x) = 8

lo g_{2} (x) + lo g_{4} (8 x) = 6

lo g_{4} (3 x - 7) = 1

lo g_{2} (x) + lo g_{4} (x) = 9

What is the answer to 2log_{4}(x+1)=log_{4}(11-x) ?
The answer to 2log_{4}(x+1)=log_{4}(11-x) is x=2
Solve for x: 2log_{4}(x+1)=log_{4}(11-x)
The solution is x=2