What is the answer to ln(2x+1)=8-ln(2x+1) ?

The answer to ln(2x+1)=8-ln(2x+1) is x=(e^4-1)/2

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ln(2x+1)=8-ln(2x+1)

ln (2 x + 1) = 8 - ln (2 x + 1)

x = \frac{e ^{4} - 1}{2}

Solution steps

ln (2 x + 1) = 8 - ln (2 x + 1)

Move

ln (2 x + 1)

to the left side

2 ln (2 x + 1) = 8

Divide both sides by

2

ln (2 x + 1) = 4

Apply log rules

2 x + 1 = e^{4}

Solve

2 x + 1 = e^{4} : x = \frac{e ^{4} - 1}{2}

x = \frac{e ^{4} - 1}{2}

Verify Solutions:

x = \frac{e ^{4} - 1}{2}

True

The solution is

x = \frac{e ^{4} - 1}{2}

2 lo g_{2} (x + 3) - lo g_{2} (x + 1) = 3

lo g_{2} (x + 2) = 1 + lo g_{2} (x - 1)

x, ln (x^{2} - 1) = 3

lo g_{b} (81) = 4

lo g_{10} (x) - lo g_{10} (8) = 1

What is the answer to ln(2x+1)=8-ln(2x+1) ?
The answer to ln(2x+1)=8-ln(2x+1) is x=(e^4-1)/2
Solve for x: ln(2x+1)=8-ln(2x+1)
The solution is x=(e^4-1)/2