What is the answer to log_{10}(x)-log_{10}(8)=1 ?

The answer to log_{10}(x)-log_{10}(8)=1 is x=80

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log_{10}(x)-log_{10}(8)=1

lo g_{10} (x) - lo g_{10} (8) = 1

x = 80

Solution steps

lo g_{10} (x) - lo g_{10} (8) = 1

Move

lo g_{10} (8)

to the right side

lo g_{10} (x) = 1 + lo g_{10} (8)

Apply log rules

x = 80

Verify Solutions:

x = 80

True

The solution is

x = 80

lo g_{4} (1.5 x) = lo g_{16} (3 x - 1)

lo g_{k} (4) = 2

lo g_{10} (3 x) + lo g_{10} (x) 9 = 3

lo g_{2} (3 x + 1) = lo g_{2} (x + 3)

2 lo g_{10} (x - 1) - lo g_{10} (x) = 0

What is the answer to log_{10}(x)-log_{10}(8)=1 ?
The answer to log_{10}(x)-log_{10}(8)=1 is x=80
Solve for x: log_{10}(x)-log_{10}(8)=1
The solution is x=80