What is the answer to solvefor x,ln(x^2-1)=3 ?

The answer to solvefor x,ln(x^2-1)=3 is x=sqrt(e^3+1),x=-sqrt(e^3+1)

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solvefor x,ln(x^2-1)=3

solve for

x, ln (x^{2} - 1) = 3

x = e^{3} + 1, x = - e^{3} + 1

Decimal Notation

x = 4.59189 \dots, x = - 4.59189 \dots

Solution steps

ln (x^{2} - 1) = 3

Apply log rules

x^{2} - 1 = e^{3}

Solve

x^{2} - 1 = e^{3} : x = e^{3} + 1, x = - e^{3} + 1

x = e^{3} + 1, x = - e^{3} + 1

lo g_{b} (81) = 4

lo g_{10} (x) - lo g_{10} (8) = 1

lo g_{4} (1.5 x) = lo g_{16} (3 x - 1)

lo g_{k} (4) = 2

lo g_{10} (3 x) + lo g_{10} (x) 9 = 3

What is the answer to solvefor x,ln(x^2-1)=3 ?
The answer to solvefor x,ln(x^2-1)=3 is x=sqrt(e^3+1),x=-sqrt(e^3+1)