What is the answer to log_{2}(x+2)=1+log_{2}(x-1) ?

The answer to log_{2}(x+2)=1+log_{2}(x-1) is x=4

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log_{2}(x+2)=1+log_{2}(x-1)

lo g_{2} (x + 2) = 1 + lo g_{2} (x - 1)

x = 4

Solution steps

lo g_{2} (x + 2) = 1 + lo g_{2} (x - 1)

Apply log rules

x + 2 = 2 (x - 1)

Solve

x + 2 = 2 (x - 1) : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

x, ln (x^{2} - 1) = 3

lo g_{b} (81) = 4

lo g_{10} (x) - lo g_{10} (8) = 1

lo g_{4} (1.5 x) = lo g_{16} (3 x - 1)

lo g_{k} (4) = 2

What is the answer to log_{2}(x+2)=1+log_{2}(x-1) ?
The answer to log_{2}(x+2)=1+log_{2}(x-1) is x=4
Solve for x: log_{2}(x+2)=1+log_{2}(x-1)
The solution is x=4