What is the answer to 2log_{2}(x+3)-log_{2}(x+1)=3 ?

The answer to 2log_{2}(x+3)-log_{2}(x+1)=3 is x=1

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2log_{2}(x+3)-log_{2}(x+1)=3

2 lo g_{2} (x + 3) - lo g_{2} (x + 1) = 3

x = 1

Solution steps

2 lo g_{2} (x + 3) - lo g_{2} (x + 1) = 3

Apply log rules

(x + 3)^{2} = 8 (x + 1)

Solve

(x + 3)^{2} = 8 (x + 1) : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{2} (x + 2) = 1 + lo g_{2} (x - 1)

x, ln (x^{2} - 1) = 3

lo g_{b} (81) = 4

lo g_{10} (x) - lo g_{10} (8) = 1

lo g_{4} (1.5 x) = lo g_{16} (3 x - 1)

What is the answer to 2log_{2}(x+3)-log_{2}(x+1)=3 ?
The answer to 2log_{2}(x+3)-log_{2}(x+1)=3 is x=1
Solve for x: 2log_{2}(x+3)-log_{2}(x+1)=3
The solution is x=1