What is the answer to 3log_{8}(2x+1)=2 ?

The answer to 3log_{8}(2x+1)=2 is x= 3/2

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3log_{8}(2x+1)=2

3 lo g_{8} (2 x + 1) = 2

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

3 lo g_{8} (2 x + 1) = 2

Divide both sides by

3

lo g_{8} (2 x + 1) = \frac{2}{3}

Apply log rules

2 x + 1 = 4

Solve

2 x + 1 = 4 : x = \frac{3}{2}

x = \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

The solution is

x = \frac{3}{2}

x, ln (y + 2) = ln (x - 3) + c

lo g_{4} (2 x^{2} - 4 x) = 2

8.4 = lo g_{10} (x)

- 9.042 = 20 lo g_{10} (x)

lo g_{3} (x^{2} + 4 x) = 4

What is the answer to 3log_{8}(2x+1)=2 ?
The answer to 3log_{8}(2x+1)=2 is x= 3/2
Solve for x: 3log_{8}(2x+1)=2
The solution is x= 3/2