What is the answer to solvefor x,ln(y+2)=ln(x-3)+c ?

The answer to solvefor x,ln(y+2)=ln(x-3)+c is x=e^{-c}y+2e^{-c}+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(y+2)=ln(x-3)+c

solve for

x, ln (y + 2) = ln (x - 3) + c

x = e^{- c} y + 2 e^{- c} + 3

Solution steps

ln (y + 2) = ln (x - 3) + c

Switch sides

ln (x - 3) + c = ln (y + 2)

Move

c

to the right side

ln (x - 3) = ln (y + 2) - c

Apply log rules

x - 3 = e^{- c} y + 2 e^{- c}

Solve

x - 3 = e^{- c} y + 2 e^{- c} : x = e^{- c} y + 2 e^{- c} + 3

x = e^{- c} y + 2 e^{- c} + 3

lo g_{4} (2 x^{2} - 4 x) = 2

8.4 = lo g_{10} (x)

- 9.042 = 20 lo g_{10} (x)

lo g_{3} (x^{2} + 4 x) = 4

lo g_{3} (81) = 4 lo g_{3} (x + 1)

What is the answer to solvefor x,ln(y+2)=ln(x-3)+c ?
The answer to solvefor x,ln(y+2)=ln(x-3)+c is x=e^{-c}y+2e^{-c}+3