What is the answer to 1=2.22+log_{10}(x) ?

The answer to 1=2.22+log_{10}(x) is x= 1/(10^{1.22)}

Solve for x: 1=2.22+log_{10}(x)

The solution is x= 1/(10^{1.22)}

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1 = 2.22 + lo g_{10} (x)

x = \frac{1}{1 0 ^{1.22}}

Solution steps

1 = 2.22 + lo g_{10} (x)

Switch sides

2.22 + lo g_{10} (x) = 1

Move

2.22

to the right side

lo g_{10} (x) = - 1.22

Apply log rules

x = \frac{1}{1 0 ^{1.22}}

Verify Solutions:

x = \frac{1}{1 0 ^{1.22}}

True

The solution is

x = \frac{1}{1 0 ^{1.22}}

lo g_{2} (8 x - 3) = 2 + lo g_{10} (2)

lo g_{3} ((x + 10)^{4}) = 4

- 20 lo g_{10} (x) = 10.2

lo g_{2} ((r + 7)^{2}) = 6

2 ln (3 x) + ln (x - 1) = 0

What is the answer to 1=2.22+log_{10}(x) ?
The answer to 1=2.22+log_{10}(x) is x= 1/(10^{1.22)}
Solve for x: 1=2.22+log_{10}(x)
The solution is x= 1/(10^{1.22)}