What are the solutions to the equation h^2-60h+100=0 ?

The solutions to the equation h^2-60h+100=0 are h=10(3+2sqrt(2)),h=10(3-2sqrt(2))

Find the zeros of h^2-60h+100=0

The zeros of h^2-60h+100=0 are h=10(3+2sqrt(2)),h=10(3-2sqrt(2))

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h^{2} - 60 h + 100 = 0

h = 10 (3 + 22), h = 10 (3 - 22)

Decimal Notation

h = 58.28427 \dots, h = 1.71572 \dots

Solution steps

h^{2} - 60 h + 100 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

(- 60)^{2} - 4 \cdot 1 \cdot 100 = 402

h_{1, 2} = \frac{- ( - 60 ) \pm 40 2}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 60 ) + 40 2}{2 \cdot 1}, h_{2} = \frac{- ( - 60 ) - 40 2}{2 \cdot 1}

h = \frac{- ( - 60 ) + 40 2}{2 \cdot 1} : 10 (3 + 22)

h = \frac{- ( - 60 ) - 40 2}{2 \cdot 1} : 10 (3 - 22)

The solutions to the quadratic equation are:

h = 10 (3 + 22), h = 10 (3 - 22)

5 (x - 5)^{2} - 33 = - 28

4 (x - 4)^{2} - 33 = - 5

2 v^{2} + 15 v + 19 = 0

0 = 2 x^{2} - 10 x + 7

- 18 x^{2} + 45 x - 25 = 0

What are the solutions to the equation h^2-60h+100=0 ?
The solutions to the equation h^2-60h+100=0 are h=10(3+2sqrt(2)),h=10(3-2sqrt(2))
Find the zeros of h^2-60h+100=0
The zeros of h^2-60h+100=0 are h=10(3+2sqrt(2)),h=10(3-2sqrt(2))