What are the solutions to the equation roots 2x^2+1 ?

The solutions to the equation roots 2x^2+1 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of roots 2x^2+1

The zeros of roots 2x^2+1 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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roots

2 x^{2} + 1

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

2 x^{2} + 1

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} + 1 = 0

Move

1

to the right side

2 x^{2} = - 1

Divide both sides by

2

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

7 x^{2} + 36 x - 1440 = 0

y, x^{2} + 14 x y + 49 y^{2} = 100

4 x (2 x - 1) = 9 - 7 x

x^{2} + 2 x + 5 = 0

x^{2} - 12 x + c = 0

What are the solutions to the equation roots 2x^2+1 ?
The solutions to the equation roots 2x^2+1 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of roots 2x^2+1
The zeros of roots 2x^2+1 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i