What are the solutions to the equation 7x^2+36x-1440=0 ?

The solutions to the equation 7x^2+36x-1440=0 are x=12,x=-120/7

Find the zeros of 7x^2+36x-1440=0

The zeros of 7x^2+36x-1440=0 are x=12,x=-120/7

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7 x^{2} + 36 x - 1440 = 0

x = 12, x = - \frac{120}{7}

Decimal Notation

x = 12, x = - 17.14285 \dots

Solution steps

7 x^{2} + 36 x - 1440 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 7 ( - 1440 )}{2 \cdot 7}

3 6^{2} - 4 \cdot 7 (- 1440) = 204

x_{1, 2} = \frac{- 36 \pm 204}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 36 + 204}{2 \cdot 7}, x_{2} = \frac{- 36 - 204}{2 \cdot 7}

x = \frac{- 36 + 204}{2 \cdot 7} : 12

x = \frac{- 36 - 204}{2 \cdot 7} : - \frac{120}{7}

The solutions to the quadratic equation are:

x = 12, x = - \frac{120}{7}

y, x^{2} + 14 x y + 49 y^{2} = 100

4 x (2 x - 1) = 9 - 7 x

x^{2} + 2 x + 5 = 0

x^{2} - 12 x + c = 0

2 x^{2} - 5 x - 3

What are the solutions to the equation 7x^2+36x-1440=0 ?
The solutions to the equation 7x^2+36x-1440=0 are x=12,x=-120/7
Find the zeros of 7x^2+36x-1440=0
The zeros of 7x^2+36x-1440=0 are x=12,x=-120/7