What are the solutions to the equation s^3+s^2+4s+4=0 ?

The solutions to the equation s^3+s^2+4s+4=0 are s=-1,s=2i,s=-2i

Find the zeros of s^3+s^2+4s+4=0

The zeros of s^3+s^2+4s+4=0 are s=-1,s=2i,s=-2i

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s^{3} + s^{2} + 4 s + 4 = 0

s = - 1, s = 2 i, s = - 2 i

Solution steps

s^{3} + s^{2} + 4 s + 4 = 0

Factor

s^{3} + s^{2} + 4 s + 4 : (s + 1) (s^{2} + 4)

(s + 1) (s^{2} + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

s + 1 = 0 or s^{2} + 4 = 0

Solve

s + 1 = 0 : s = - 1

Solve

s^{2} + 4 = 0 : s = 2 i, s = - 2 i

The solutions are

s = - 1, s = 2 i, s = - 2 i

(- 11 x^{2} + 62) (- 9 x^{2} + 25) - (- 11) (- 11) = 0

1 - \frac{5}{2} x + 2 x^{2} - \frac{1}{2} x^{3} = 0

10 x^{3} - 39 x^{2} + 29 x - 6 = 0

4 x^{3} - 54 x^{2} + 240 x - 350 = 0

x^{3} - 64 = 0

What are the solutions to the equation s^3+s^2+4s+4=0 ?
The solutions to the equation s^3+s^2+4s+4=0 are s=-1,s=2i,s=-2i
Find the zeros of s^3+s^2+4s+4=0
The zeros of s^3+s^2+4s+4=0 are s=-1,s=2i,s=-2i