What is the integral from 0 to 1 of (49)/(x^5) ?

The integral from 0 to 1 of (49)/(x^5) is diverges

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integral from 0 to 1 of (49)/(x^5)

\int_{0}^{1} \frac{49}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{49}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 49 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 49 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

7 x, at x = 4

\int 8 u^{\frac{9}{8}} d u

x = y^{2} - 2, (- 2, 2)

y^{'} = y (1 - 0.0008 y)

f (x) = \frac{2 x}{x - 1}

What is the integral from 0 to 1 of (49)/(x^5) ?
The integral from 0 to 1 of (49)/(x^5) is diverges