What is the derivative of f(x)=arccos(2x) ?

The derivative of f(x)=arccos(2x) is -2/(sqrt(1-4x^2))

What is the first derivative of f(x)=arccos(2x) ?

The first derivative of f(x)=arccos(2x) is -2/(sqrt(1-4x^2))

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derivative of

f (x) = arccos (2 x)

- \frac{2}{1 - 4 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (2 x))

Apply the chain rule:

- \frac{1}{1 - ( 2 x ) ^{2}} \frac{d}{d x} (2 x)

= - \frac{1}{1 - ( 2 x ) ^{2}} \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - \frac{1}{1 - ( 2 x ) ^{2}} \cdot 2

Simplify

- \frac{1}{1 - ( 2 x ) ^{2}} \cdot 2 : - \frac{2}{1 - 4 x ^{2}}

= - \frac{2}{1 - 4 x ^{2}}

(- 10, - 7), (- 5, - 9)

f (x) = arctan (\frac{2 x}{1 - x ^{2}})

\frac{\partial}{\partial s} (1 + s t)

\int \frac{11 x + 64}{x ^{2} + 13 x + 40} d x

What is the derivative of f(x)=arccos(2x) ?
The derivative of f(x)=arccos(2x) is -2/(sqrt(1-4x^2))
What is the first derivative of f(x)=arccos(2x) ?
The first derivative of f(x)=arccos(2x) is -2/(sqrt(1-4x^2))