Solution
Solution
Solution steps
Use the Ratio Test to compute the convergence interval
Popular Examples
limit as x approaches-9 of (x^2-4)/(x-9)limit as x approaches infinity of x^4e^{-x^3}sum from n=0 to infinity of 1/(n+1)integral of (sqrt(x^2-16))/(x^3)tangent of f(x)=(2ln(x))/x ,\at x=1
Frequently Asked Questions (FAQ)
What is the sum from n=3 to infinity}((ln(x))^{n-1 of)/(2^n) ?
The sum from n=3 to infinity}((ln(x))^{n-1 of)/(2^n) is Interval of convergence is 1/(e^2)<x<e^2