What is the integral of e^{-0.89x} ?

The integral of e^{-0.89x} is -1.12359…e^{-0.89x}+C

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integral of e^{-0.89x}

\int e^{- 0.89 x} d x

- 1.12359 \dots e^{- 0.89 x} + C

Solution steps

\int e^{- 0.89 x} d x

Apply u-substitution

: \int - \frac{1}{0.89} e^{u} d u

= \int - \frac{1}{0.89} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{0.89} \cdot \int e^{u} d u

Simplify

= - 1.12359 \dots \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 1.12359 \dots e^{u}

Substitute back

u = - 0.89 x

= - 1.12359 \dots e^{- 0.89 x}

Add a constant to the solution

= - 1.12359 \dots e^{- 0.89 x} + C

\frac{\partial}{\partial y} (- y cos (x))

\frac{s + 1}{( s + 1 ) ( s ^{2} + 2 )}

y = - x^{2} + 2 x + 2, y = x - 4

\int \frac{d ^{2} y}{1} d x^{2}

\int (sin^{2} (x) + cos^{2} (x) - 1) d x

What is the integral of e^{-0.89x} ?
The integral of e^{-0.89x} is -1.12359…e^{-0.89x}+C