What is the integral from 2 to 5 of sin(x) ?

The integral from 2 to 5 of sin(x) is -cos(5)+cos(2)

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integral from 2 to 5 of sin(x)

\int_{2}^{5} sin (x) d x

- cos (5) + cos (2)

Decimal Notation

- 0.69980 \dots

Solution steps

\int_{2}^{5} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{2}^{5}

Compute the boundaries:

- cos (5) + cos (2)

= - cos (5) + cos (2)

\int_{0}^{1} x^{14} + 1 4^{x} d x

\int_{0}^{π} sin (8 x + π) d x

\int_{- 1}^{2} ∣ 1 - x ∣ d x

\int_{0}^{π} 4 cos^{2} (x) d x

\int_{- 1}^{0} x^{\frac{1}{3}} - x d x

What is the integral from 2 to 5 of sin(x) ?
The integral from 2 to 5 of sin(x) is -cos(5)+cos(2)