What is the limit as x approaches 0+of 6-1/(x^3) ?

The limit as x approaches 0+of 6-1/(x^3) is -infinity

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limit as x approaches 0+of 6-1/(x^3)

x \to 0 + lim (6 - \frac{1}{x ^{3}})

- \infty

Solution steps

x \to 0 + lim (6 - \frac{1}{x ^{3}})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (6) - x \to 0 + lim (\frac{1}{x ^{3}})

x \to 0 + lim (6) = 6

x \to 0 + lim (\frac{1}{x ^{3}}) = \infty

= 6 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

t^{2} y^{^{''}} - 8 t y^{^{'}} + 8 y = 0

\int 6 x ln (x) d x

sin (t^{2})

\int t e^{- i 2 π f t} d t

\int_{0}^{π} cos (3 x) d x

What is the limit as x approaches 0+of 6-1/(x^3) ?
The limit as x approaches 0+of 6-1/(x^3) is -infinity