What is the integral from 0 to ln(2) of 10e^{2t} ?

The integral from 0 to ln(2) of 10e^{2t} is 15

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integral from 0 to ln(2) of 10e^{2t}

\int_{0}^{l n (2)} 10 e^{2 t} d t

15

Solution steps

\int_{0}^{l n (2)} 10 e^{2 t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{0}^{l n (2)} e^{2 t} d t

Apply u-substitution

: \int_{0}^{2 l n (2)} e^{u} \frac{1}{2} d u

= 10 \cdot \int_{0}^{2 l n (2)} e^{u} \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{2} \cdot \int_{0}^{2 l n (2)} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 10 \cdot \frac{1}{2} [e^{u}]_{0}^{2 l n (2)}

Simplify

10 \cdot \frac{1}{2} [e^{u}]_{0}^{2 l n (2)} : 5 [e^{u}]_{0}^{2 l n (2)}

= 5 [e^{u}]_{0}^{2 l n (2)}

Compute the boundaries:

3

= 5 \cdot 3

Simplify

= 15

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What is the integral from 0 to ln(2) of 10e^{2t} ?
The integral from 0 to ln(2) of 10e^{2t} is 15