What is the inverse of f(x)= 1/3 x^2+5 ?

The inverse of f(x)= 1/3 x^2+5 is sqrt(3x-15),-sqrt(3x-15)

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inverse of f(x)= 1/3 x^2+5

inverse

f (x) = \frac{1}{3} x^{2} + 5

3 x - 15, - 3 x - 15

Solution steps

y = \frac{1}{3} x^{2} + 5

Replace

x

with

y

x = \frac{1}{3} y^{2} + 5

Solve for

y, x = \frac{1}{3} y^{2} + 5

3 x - 15, - 3 x - 15

f (x) = lo g_{2} (lo g_{10} (x))

f (x) = \frac{- 8}{x ^{2} - 4}

\frac{2 y + 6}{3 y + 2}

f (x) = f (x) = x^{2} + 2

f (x) = \frac{3 - 4 x}{5 x + 1}

What is the inverse of f(x)= 1/3 x^2+5 ?
The inverse of f(x)= 1/3 x^2+5 is sqrt(3x-15),-sqrt(3x-15)