What is the domain of f(x)=(x^2+x+1)^{-3/2} ?

The domain of f(x)=(x^2+x+1)^{-3/2} is -infinity <x<infinity

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domain of f(x)=(x^2+x+1)^{-3/2}

domain

f (x) = (x^{2} + x + 1)^{- \frac{3}{2}}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 4 x^{4} - 16

f (x) = - \frac{1}{2} x

f (x) = \frac{1}{6 x ^{2} - 18 x - 60}

f (x) = 3 x^{2} - 6 x

f (x) = 36 - x^{2} - x + 2

What is the domain of f(x)=(x^2+x+1)^{-3/2} ?
The domain of f(x)=(x^2+x+1)^{-3/2} is -infinity <x<infinity