What is the inverse of f(x)=1-2x^2 ?

The inverse of f(x)=1-2x^2 is sqrt(-(x-1)/2),-sqrt(-(x-1)/2)

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inverse of f(x)=1-2x^2

inverse

f (x) = 1 - 2 x^{2}

- \frac{x - 1}{2}, - - \frac{x - 1}{2}

Solution steps

y = 1 - 2 x^{2}

Replace

x

with

y

x = 1 - 2 y^{2}

Solve for

y, x = 1 - 2 y^{2}

- \frac{x - 1}{2}, - - \frac{x - 1}{2}

f (d) = \frac{d + 12}{2 d + 1}

f (x) = \frac{9 x}{x - 6}

f (x) = \frac{( 17 x - 6 )}{- 9 x - 3}

f (x) = 7 (x^{\frac{1}{5}} + 7)

f (s) = \frac{1}{s ^{3} + a ^{3}}

What is the inverse of f(x)=1-2x^2 ?
The inverse of f(x)=1-2x^2 is sqrt(-(x-1)/2),-sqrt(-(x-1)/2)