What is x^2+y^2+6x-8y+9=0 ?

The solution to x^2+y^2+6x-8y+9=0 is Circle with (a,b)=(-3,4),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+6x-8y+9=0

x^{2} + y^{2} + 6 x - 8 y + 9 = 0

(a, b) = (- 3, 4), r = 4

Solution steps

x^{2} + y^{2} + 6 x - 8 y + 9 = 0

Rewrite

x^{2} + y^{2} + 6 x - 8 y + 9 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 4

x^{2} + y^{2} - 5 x = 0

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

(x^{2} + 4 x + 4) + (y^{2} - 8 y + 16) = - 9 + 4 + 16

(x - 20)^{2} + (y - 0.05)^{2} = 81

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

What is x^2+y^2+6x-8y+9=0 ?
The solution to x^2+y^2+6x-8y+9=0 is Circle with (a,b)=(-3,4),r=4