What is (x-6)^2+(y-(-2))^2=25 ?

The solution to (x-6)^2+(y-(-2))^2=25 is Circle with (a,b)=(6,-2),r=5

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(x-6)^2+(y-(-2))^2=25

(x - 6)^{2} + (y - (- 2))^{2} = 25

(a, b) = (6, - 2), r = 5

Solution steps

(x - 6)^{2} + (y - (- 2))^{2} = 25

Rewrite

(x - 6)^{2} + (y - (- 2))^{2} = 25

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 2))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (6, - 2), r = 5

x^{2} + y^{2} - 8 x - 1 y - 74 = 0

0.5 y^{2} = - 0.5 x^{2} + 12.5

p^{2} + q^{2} = 1

x^{2} + y^{2} + 14 x - 6 y - 6 = 0

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

What is (x-6)^2+(y-(-2))^2=25 ?
The solution to (x-6)^2+(y-(-2))^2=25 is Circle with (a,b)=(6,-2),r=5