What is x^2+y^2-8x-1y-74=0 ?

The solution to x^2+y^2-8x-1y-74=0 is Circle with (a,b)=(4, 1/2),r= 19/2

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x^2+y^2-8x-1y-74=0

x^{2} + y^{2} - 8 x - 1 y - 74 = 0

(a, b) = (4, \frac{1}{2}), r = \frac{19}{2}

Solution steps

x^{2} + y^{2} - 8 x - 1 \cdot y - 74 = 0

Rewrite

x^{2} + y^{2} - 8 x - 1 y - 74 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - \frac{1}{2})^{2} = (\frac{19}{2})^{2}

Therefore the circle properties are:

(a, b) = (4, \frac{1}{2}), r = \frac{19}{2}

0.5 y^{2} = - 0.5 x^{2} + 12.5

p^{2} + q^{2} = 1

x^{2} + y^{2} + 14 x - 6 y - 6 = 0

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

What is x^2+y^2-8x-1y-74=0 ?
The solution to x^2+y^2-8x-1y-74=0 is Circle with (a,b)=(4, 1/2),r= 19/2