What is ((x-1)^2)/4-((y-2)^2)/(16)=1 ?

The solution to ((x-1)^2)/4-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(1,2),a=2,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/4-((y-2)^2)/(16)=1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

(h, k) = (1, 2), a = 2, b = 4

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{2 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 2, b = 4

x^{2} - y^{2} - 2 x - 6 y - 12 = 0

16 x^{2} - 9 y^{2} + 96 = 0

\frac{( x - 3 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

(\frac{( x - 2 )}{16})^{2} - \frac{( y + 3 ) ^{2}}{1} = 1

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

What is ((x-1)^2)/4-((y-2)^2)/(16)=1 ?
The solution to ((x-1)^2)/4-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(1,2),a=2,b=4