What is 16x^2-9y^2+96=0 ?

The solution to 16x^2-9y^2+96=0 is Hyperbola with (h,k)=(0,0),a=(4sqrt(2))/(sqrt(3)),b=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16x^2-9y^2+96=0

16 x^{2} - 9 y^{2} + 96 = 0

(h, k) = (0, 0), a = \frac{4 2}{3}, b = 6

Solution steps

16 x^{2} - 9 y^{2} + 96 = 0

Rewrite

16 x^{2} - 9 y^{2} + 96 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{4 2}{3} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( 6 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{4 2}{3}, b = 6

\frac{( x - 3 ) ^{2}}{9} - \frac{( y + 2 ) ^{2}}{4} = 1

(\frac{( x - 2 )}{16})^{2} - \frac{( y + 3 ) ^{2}}{1} = 1

(3 x - 3)^{2} - (2 y - 4)^{2} = 43 + 9 + 16

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = 1

25 x^{2} - 36 y^{2} - 200 x + 360 y - 1400 = 0

What is 16x^2-9y^2+96=0 ?
The solution to 16x^2-9y^2+96=0 is Hyperbola with (h,k)=(0,0),a=(4sqrt(2))/(sqrt(3)),b=sqrt(6)