What is (x^2)/(8^2)-(y^2)/(5^2)=1 ?

The solution to (x^2)/(8^2)-(y^2)/(5^2)=1 is Hyperbola with (h,k)=(0,0),a=8,b=5

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(x^2)/(8^2)-(y^2)/(5^2)=1

\frac{x ^{2}}{8 ^{2}} - \frac{y ^{2}}{5 ^{2}} = 1

(h, k) = (0, 0), a = 8, b = 5

Solution steps

\frac{x ^{2}}{8 ^{2}} - \frac{y ^{2}}{5 ^{2}} = 1

Rewrite

\frac{x ^{2}}{8 ^{2}} - \frac{y ^{2}}{5 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} - \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 8, b = 5

4 y^{2} - x^{2} + 16 y + 12 = 0

3 x^{2} - 3 y^{2} + x + y + 1 = 0

- 4 x^{2} + y^{2} - 40 x - 16 = 0

x^{2} + 8 x - y^{2} - 4 y = 5

- 9 y^{2} + 9 z^{2} = 4

What is (x^2)/(8^2)-(y^2)/(5^2)=1 ?
The solution to (x^2)/(8^2)-(y^2)/(5^2)=1 is Hyperbola with (h,k)=(0,0),a=8,b=5