Is cos^2(x)+sin(x)tan(x)=sec(x) ?

The answer to whether cos^2(x)+sin(x)tan(x)=sec(x) is False

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prove cos^2(x)+sin(x)tan(x)=sec(x)

prove

cos^{2} (x) + sin (x) tan (x) = sec (x)

False

Solution steps

cos^{2} (x) + sin (x) tan (x) = sec (x)

Show that the two sides are not equal

For

cos^{2} (x) + sin (x) tan (x) = sec (x)

plug in

x = 1

cos^{2} (1) + sin (1) tan (1) = 1.60243 \dots

cos^{2} (1) + sin (1) tan (1)

Refine to a decimal form

= 1.60243 \dots

sec (1) = 1.85081 \dots

sec (1)

Refine to a decimal form

= 1.85081 \dots

The two sides are not equal

\Rightarrow False

\frac{1}{1 - sin ( x )} = - csc (x)

cos^{2} (x) - cos^{2} (x) = cot^{2} (x) cos^{2} (x)

2 cos (2 (\frac{π}{4})) = 16 cos (2 (\frac{π}{4}))

- sin (θ) = - sin (- θ)

- 8 cos (2 x) - (0) (2 cos (2 x)) = - 8 cos (2 x)

Is cos^2(x)+sin(x)tan(x)=sec(x) ?
The answer to whether cos^2(x)+sin(x)tan(x)=sec(x) is False