What are the solutions to the equation x(x+1)=56 ?

The solutions to the equation x(x+1)=56 are x=7,x=-8

Find the zeros of x(x+1)=56

The zeros of x(x+1)=56 are x=7,x=-8

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x (x + 1) = 56

x = 7, x = - 8

Solution steps

x (x + 1) = 56

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 56

Move

56

to the left side

x^{2} + x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 56) = 15

x_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 15}{2 \cdot 1}, x_{2} = \frac{- 1 - 15}{2 \cdot 1}

x = \frac{- 1 + 15}{2 \cdot 1} : 7

x = \frac{- 1 - 15}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 7, x = - 8

(x - 2)^{2} + 16 = 25

6 x^{2} - 5 x - 3 = 0

(s^{2} + 1) = 0

- 3 x^{2} + 12 x - 12 = 0

8 x^{2} + 14 x + 40 = 7 x^{2}

What are the solutions to the equation x(x+1)=56 ?
The solutions to the equation x(x+1)=56 are x=7,x=-8
Find the zeros of x(x+1)=56
The zeros of x(x+1)=56 are x=7,x=-8