What are the solutions to the equation 6x^2-5x-3=0 ?

The solutions to the equation 6x^2-5x-3=0 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)

Find the zeros of 6x^2-5x-3=0

The zeros of 6x^2-5x-3=0 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)

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6 x^{2} - 5 x - 3 = 0

x = \frac{5 + 97}{12}, x = \frac{5 - 97}{12}

Decimal Notation

x = 1.23740 \dots, x = - 0.40407 \dots

Solution steps

6 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 3) = 97

x_{1, 2} = \frac{- ( - 5 ) \pm 97}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 97}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 97}{2 \cdot 6}

x = \frac{- ( - 5 ) + 97}{2 \cdot 6} : \frac{5 + 97}{12}

x = \frac{- ( - 5 ) - 97}{2 \cdot 6} : \frac{5 - 97}{12}

The solutions to the quadratic equation are:

x = \frac{5 + 97}{12}, x = \frac{5 - 97}{12}

(s^{2} + 1) = 0

- 3 x^{2} + 12 x - 12 = 0

8 x^{2} + 14 x + 40 = 7 x^{2}

x^{2} + 2 a x + a^{2} = 0

- x^{2} + 6 x - 8

What are the solutions to the equation 6x^2-5x-3=0 ?
The solutions to the equation 6x^2-5x-3=0 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)
Find the zeros of 6x^2-5x-3=0
The zeros of 6x^2-5x-3=0 are x=(5+sqrt(97))/(12),x=(5-sqrt(97))/(12)