What are the solutions to the equation (x-2)^2+16=25 ?

The solutions to the equation (x-2)^2+16=25 are x=5,x=-1

Find the zeros of (x-2)^2+16=25

The zeros of (x-2)^2+16=25 are x=5,x=-1

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(x - 2)^{2} + 16 = 25

x = 5, x = - 1

Solution steps

(x - 2)^{2} + 16 = 25

Move

16

to the right side

(x - 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 9 : x = 5

Solve

x - 2 = - 9 : x = - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

6 x^{2} - 5 x - 3 = 0

(s^{2} + 1) = 0

- 3 x^{2} + 12 x - 12 = 0

8 x^{2} + 14 x + 40 = 7 x^{2}

x^{2} + 2 a x + a^{2} = 0

What are the solutions to the equation (x-2)^2+16=25 ?
The solutions to the equation (x-2)^2+16=25 are x=5,x=-1
Find the zeros of (x-2)^2+16=25
The zeros of (x-2)^2+16=25 are x=5,x=-1