What are the solutions to the equation 5x^2-20x-12=0 ?

The solutions to the equation 5x^2-20x-12=0 are x=(2(5+2sqrt(10)))/5 ,x=(2(5-2sqrt(10)))/5

Find the zeros of 5x^2-20x-12=0

The zeros of 5x^2-20x-12=0 are x=(2(5+2sqrt(10)))/5 ,x=(2(5-2sqrt(10)))/5

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5 x^{2} - 20 x - 12 = 0

x = \frac{2 ( 5 + 2 10 )}{5}, x = \frac{2 ( 5 - 2 10 )}{5}

Decimal Notation

x = 4.52982 \dots, x = - 0.52982 \dots

Solution steps

5 x^{2} - 20 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 (- 12) = 810

x_{1, 2} = \frac{- ( - 20 ) \pm 8 10}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 8 10}{2 \cdot 5}, x_{2} = \frac{- ( - 20 ) - 8 10}{2 \cdot 5}

x = \frac{- ( - 20 ) + 8 10}{2 \cdot 5} : \frac{2 ( 5 + 2 10 )}{5}

x = \frac{- ( - 20 ) - 8 10}{2 \cdot 5} : \frac{2 ( 5 - 2 10 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 5 + 2 10 )}{5}, x = \frac{2 ( 5 - 2 10 )}{5}

4 x^{2} + x - \frac{1}{16} = 0

9 x^{2} - 6 x + 1 = 0

(x - 2)^{2} - 5 = 0

(2 w + 1) w = 66

a, x = a^{2} + b^{2} + c^{3}

What are the solutions to the equation 5x^2-20x-12=0 ?
The solutions to the equation 5x^2-20x-12=0 are x=(2(5+2sqrt(10)))/5 ,x=(2(5-2sqrt(10)))/5
Find the zeros of 5x^2-20x-12=0
The zeros of 5x^2-20x-12=0 are x=(2(5+2sqrt(10)))/5 ,x=(2(5-2sqrt(10)))/5