What are the solutions to the equation 4x^2+x-1/16 =0 ?

The solutions to the equation 4x^2+x-1/16 =0 are x=(-1+sqrt(2))/8 ,x=-(1+sqrt(2))/8

Find the zeros of 4x^2+x-1/16 =0

The zeros of 4x^2+x-1/16 =0 are x=(-1+sqrt(2))/8 ,x=-(1+sqrt(2))/8

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4 x^{2} + x - \frac{1}{16} = 0

x = \frac{- 1 + 2}{8}, x = - \frac{1 + 2}{8}

Solution steps

4 x^{2} + x - \frac{1}{16} = 0

Multiply both sides by

16

64 x^{2} + 16 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 64 ( - 1 )}{2 \cdot 64}

1 6^{2} - 4 \cdot 64 (- 1) = 162

x_{1, 2} = \frac{- 16 \pm 16 2}{2 \cdot 64}

Separate the solutions

x_{1} = \frac{- 16 + 16 2}{2 \cdot 64}, x_{2} = \frac{- 16 - 16 2}{2 \cdot 64}

x = \frac{- 16 + 16 2}{2 \cdot 64} : \frac{- 1 + 2}{8}

x = \frac{- 16 - 16 2}{2 \cdot 64} : - \frac{1 + 2}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2}{8}, x = - \frac{1 + 2}{8}

9 x^{2} - 6 x + 1 = 0

(x - 2)^{2} - 5 = 0

(2 w + 1) w = 66

a, x = a^{2} + b^{2} + c^{3}

x^{2} - 3 x = 7 x^{2} + 5 x

What are the solutions to the equation 4x^2+x-1/16 =0 ?
The solutions to the equation 4x^2+x-1/16 =0 are x=(-1+sqrt(2))/8 ,x=-(1+sqrt(2))/8
Find the zeros of 4x^2+x-1/16 =0
The zeros of 4x^2+x-1/16 =0 are x=(-1+sqrt(2))/8 ,x=-(1+sqrt(2))/8