What are the solutions to the equation 32=25x^2-4 ?

The solutions to the equation 32=25x^2-4 are x= 6/5 ,x=-6/5

Find the zeros of 32=25x^2-4

The zeros of 32=25x^2-4 are x= 6/5 ,x=-6/5

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32 = 25 x^{2} - 4

x = \frac{6}{5}, x = - \frac{6}{5}

Solution steps

32 = 25 x^{2} - 4

Switch sides

25 x^{2} - 4 = 32

Move

4

to the right side

25 x^{2} = 36

Divide both sides by

25

x^{2} = \frac{36}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{36}{25}, x = - \frac{36}{25}

\frac{36}{25} = \frac{6}{5}

- \frac{36}{25} = - \frac{6}{5}

x = \frac{6}{5}, x = - \frac{6}{5}

- 12 x = 3 - 5 x^{2}

4 k^{2} + 41 k + 10 = 0

x^{2} - 6 x + 5 = - 4

3 k^{2} - 4 k - 4 = k

(3 x + 9)^{2} = 81

What are the solutions to the equation 32=25x^2-4 ?
The solutions to the equation 32=25x^2-4 are x= 6/5 ,x=-6/5
Find the zeros of 32=25x^2-4
The zeros of 32=25x^2-4 are x= 6/5 ,x=-6/5