What are the solutions to the equation (2x-3)(3x+5)=-14 ?

The solutions to the equation (2x-3)(3x+5)=-14 are x= 1/3 ,x=-1/2

Find the zeros of (2x-3)(3x+5)=-14

The zeros of (2x-3)(3x+5)=-14 are x= 1/3 ,x=-1/2

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(2 x - 3) (3 x + 5) = - 14

x = \frac{1}{3}, x = - \frac{1}{2}

Solution steps

(2 x - 3) (3 x + 5) = - 14

Expand

(2 x - 3) (3 x + 5) : 6 x^{2} + x - 15

6 x^{2} + x - 15 = - 14

Move

14

to the left side

6 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 6}, x_{2} = \frac{- 1 - 5}{2 \cdot 6}

x = \frac{- 1 + 5}{2 \cdot 6} : \frac{1}{3}

x = \frac{- 1 - 5}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{1}{2}

(x - 1) (x + 4) = 1

x^{2} - 6 x = 18

15 + 26 d = - 8 d^{2}

y^{2} - 9 y = - 14

w^{2} - 4 = 12

What are the solutions to the equation (2x-3)(3x+5)=-14 ?
The solutions to the equation (2x-3)(3x+5)=-14 are x= 1/3 ,x=-1/2
Find the zeros of (2x-3)(3x+5)=-14
The zeros of (2x-3)(3x+5)=-14 are x= 1/3 ,x=-1/2