What are the solutions to the equation (x-1)(x+4)=1 ?

The solutions to the equation (x-1)(x+4)=1 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2

Find the zeros of (x-1)(x+4)=1

The zeros of (x-1)(x+4)=1 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2

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(x - 1) (x + 4) = 1

x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

Decimal Notation

x = 1.19258 \dots, x = - 4.19258 \dots

Solution steps

(x - 1) (x + 4) = 1

Expand

(x - 1) (x + 4) : x^{2} + 3 x - 4

x^{2} + 3 x - 4 = 1

Move

1

to the left side

x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 5) = 29

x_{1, 2} = \frac{- 3 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 29}{2 \cdot 1}, x_{2} = \frac{- 3 - 29}{2 \cdot 1}

x = \frac{- 3 + 29}{2 \cdot 1} : \frac{- 3 + 29}{2}

x = \frac{- 3 - 29}{2 \cdot 1} : \frac{- 3 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

x^{2} - 6 x = 18

15 + 26 d = - 8 d^{2}

y^{2} - 9 y = - 14

w^{2} - 4 = 12

5 p^{2} + 11 p + 6 = 0

What are the solutions to the equation (x-1)(x+4)=1 ?
The solutions to the equation (x-1)(x+4)=1 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2
Find the zeros of (x-1)(x+4)=1
The zeros of (x-1)(x+4)=1 are x=(-3+sqrt(29))/2 ,x=(-3-sqrt(29))/2