What are the solutions to the equation x^2-6x=18 ?

The solutions to the equation x^2-6x=18 are x=3(1+sqrt(3)),x=3(1-sqrt(3))

Find the zeros of x^2-6x=18

The zeros of x^2-6x=18 are x=3(1+sqrt(3)),x=3(1-sqrt(3))

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x^{2} - 6 x = 18

x = 3 (1 + 3), x = 3 (1 - 3)

Decimal Notation

x = 8.19615 \dots, x = - 2.19615 \dots

Solution steps

x^{2} - 6 x = 18

Move

18

to the left side

x^{2} - 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 18) = 63

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6 3}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6 3}{2 \cdot 1} : 3 (1 + 3)

x = \frac{- ( - 6 ) - 6 3}{2 \cdot 1} : 3 (1 - 3)

The solutions to the quadratic equation are:

x = 3 (1 + 3), x = 3 (1 - 3)

15 + 26 d = - 8 d^{2}

y^{2} - 9 y = - 14

w^{2} - 4 = 12

5 p^{2} + 11 p + 6 = 0

(2 x + 4) (x - 3) = 0

What are the solutions to the equation x^2-6x=18 ?
The solutions to the equation x^2-6x=18 are x=3(1+sqrt(3)),x=3(1-sqrt(3))
Find the zeros of x^2-6x=18
The zeros of x^2-6x=18 are x=3(1+sqrt(3)),x=3(1-sqrt(3))