What are the solutions to the equation 4x^2-12x+9=0 ?

The solutions to the equation 4x^2-12x+9=0 are x= 3/2

Find the zeros of 4x^2-12x+9=0

The zeros of 4x^2-12x+9=0 are x= 3/2

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4 x^{2} - 12 x + 9 = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

4 b^{2} - 8 b - 10 = - 5

25 x^{2} - 8 x = 12 x - 4

3 x^{2} - 5 = 25

- 16 t^{2} - 20 t + 700 = 0

10 c^{2} + 9 c - 1 = 6 c^{2}

What are the solutions to the equation 4x^2-12x+9=0 ?
The solutions to the equation 4x^2-12x+9=0 are x= 3/2
Find the zeros of 4x^2-12x+9=0
The zeros of 4x^2-12x+9=0 are x= 3/2