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Popular Algebra Problems
x^2>11-4x
x^{2}>11-4x
6d-11/2 =2d-13/2
6d-\frac{11}{2}=2d-\frac{13}{2}
simplify 1-(365!)/(365^{23)(365-23)!}
simplify\:1-\frac{365!}{365^{23}(365-23)!}
simplify (3a-b)^2+3(a+b)^2
simplify\:(3a-b)^{2}+3(a+b)^{2}
x^2+8=84
x^{2}+8=84
simplify 2\sqrt[3]{6}*2^{2/3}x^5\sqrt[3]{x}
simplify\:2\sqrt[3]{6}\cdot\:2^{\frac{2}{3}}x^{5}\sqrt[3]{x}
factor y^2-9x^2
factor\:y^{2}-9x^{2}
|5y-5|=|4y+6|
\left|5y-5\right|=\left|4y+6\right|
x/5+4>-3
\frac{x}{5}+4>-3
(x+8)(x+15)=0
(x+8)(x+15)=0
x^2+(x+1)^2+(x+2)^2+(x+3)^2=54
x^{2}+(x+1)^{2}+(x+2)^{2}+(x+3)^{2}=54
simplify (8x^7x)/(12x^5yz^{-2)}
simplify\:\frac{8x^{7}x}{12x^{5}yz^{-2}}
factor x^2-5x-6
factor\:x^{2}-5x-6
simplify 2/((3)^{3/2)}
simplify\:\frac{2}{(3)^{\frac{3}{2}}}
(5x-8)/7 =-5x+16
\frac{5x-8}{7}=-5x+16
factor 8m^6-2m^2
factor\:8m^{6}-2m^{2}
3x^2+5=5x
3x^{2}+5=5x
simplify (16b^2+32b+16)/(4b+4)
simplify\:\frac{16b^{2}+32b+16}{4b+4}
x/6+1/2 = 1/12
\frac{x}{6}+\frac{1}{2}=\frac{1}{12}
|x^2-2x|=15
\left|x^{2}-2x\right|=15
factor 22x^2-25xy+7y^2
factor\:22x^{2}-25xy+7y^{2}
24pi=r(pi/4)
24π=r(\frac{π}{4})
factor 56k^4-24k^3+40k^2
factor\:56k^{4}-24k^{3}+40k^{2}
14+8m=14-3m-5m
14+8m=14-3m-5m
(x+2)^2+7(x+2)+12=0
(x+2)^{2}+7(x+2)+12=0
2x=2x
2x=2x
5/6 x-2x+4/3 = 5/3
\frac{5}{6}x-2x+\frac{4}{3}=\frac{5}{3}
6x+11=21
6x+11=21
48+x=180
48+x=180
factor 25a^2-9
factor\:25a^{2}-9
6y+5=8y+11
6y+5=8y+11
4(x-1)>= 2x+6
4(x-1)\ge\:2x+6
-3u+12u+6=7u+30
-3u+12u+6=7u+30
|4x+3|=2x-1
\left|4x+3\right|=2x-1
simplify sqrt(-49)
simplify\:\sqrt{-49}
20x^2+7x-6=0
20x^{2}+7x-6=0
x^2-4>3x
x^{2}-4>3x
x+7=5
x+7=5
-7+10z>-27
-7+10z>-27
simplify (5xy^3)/(125x^2y^7)
simplify\:\frac{5xy^{3}}{125x^{2}y^{7}}
simplify (y^4)^{1/6}
simplify\:(y^{4})^{\frac{1}{6}}
(x-1)(x-2)(x-6)<= 0
(x-1)(x-2)(x-6)\le\:0
6x+11=-(6x+5)
6x+11=-(6x+5)
x^2+5x-8=4x+4
x^{2}+5x-8=4x+4
2x^2+x>= 28
2x^{2}+x\ge\:28
1/x+1/3 < 1/5
\frac{1}{x}+\frac{1}{3}<\frac{1}{5}
6x^2+x-2=0
6x^{2}+x-2=0
1/4
\frac{1}{4}
t+3>= 7
t+3\ge\:7
simplify 2/4-1/3
simplify\:\frac{2}{4}-\frac{1}{3}
5x-15-7x=4x+3
5x-15-7x=4x+3
factor-15a^5+9ab^3
factor\:-15a^{5}+9ab^{3}
(5x-3)^2=36
(5x-3)^{2}=36
8x^2-17x+8=0
8x^{2}-17x+8=0
xsqrt(2)=88
x\sqrt{2}=88
factor 10g^3+15g^2-12g-18
factor\:10g^{3}+15g^{2}-12g-18
x^2+9x-10>= 0
x^{2}+9x-10\ge\:0
simplify (x^{-5}y^3z^{10})^{-3/5}
simplify\:(x^{-5}y^{3}z^{10})^{-\frac{3}{5}}
x/3-1=4
\frac{x}{3}-1=4
simplify ((sqrt(7))/4)/(3/4)
simplify\:\frac{\frac{\sqrt{7}}{4}}{\frac{3}{4}}
factor z^5+5z^4-25z^3-125z^2
factor\:z^{5}+5z^{4}-25z^{3}-125z^{2}
11t-1.86t^2=0
11t-1.86t^{2}=0
3x^2-10x-1=0
3x^{2}-10x-1=0
2-x/(x+1)>3-9/(x+1)
2-\frac{x}{x+1}>3-\frac{9}{x+1}
simplify (y^4)^2
simplify\:(y^{4})^{2}
x^2>x
x^{2}>x
3(c+2)=36
3(c+2)=36
x^2+5x=-6
x^{2}+5x=-6
16x=30
16x=30
simplify log_{3}(9x)
simplify\:\log_{3}(9x)
simplify (18!)/(11!(7!))
simplify\:\frac{18!}{11!(7!)}
simplify (5/2)^4+1
simplify\:(\frac{5}{2})^{4}+1
3/2 x-4=16
\frac{3}{2}x-4=16
-2(m+3)<-3-3m
-2(m+3)<-3-3m
factor 6x^3+48
factor\:6x^{3}+48
1.5x+4(323-x)=822
1.5x+4(323-x)=822
simplify 2/(3+sqrt(2))
simplify\:\frac{2}{3+\sqrt{2}}
2-3d=-25
2-3d=-25
simplify (25x^2y^5)/(5x^4y^3)
simplify\:\frac{25x^{2}y^{5}}{5x^{4}y^{3}}
5x=13
5x=13
factor 8x^3-125
factor\:8x^{3}-125
((2x+7))/3-((3x-6))/4+((4x+9))/6 =((x+3))/2
\frac{(2x+7)}{3}-\frac{(3x-6)}{4}+\frac{(4x+9)}{6}=\frac{(x+3)}{2}
-16t^2+1354=0
-16t^{2}+1354=0
simplify 4/52*4/52
simplify\:\frac{4}{52}\cdot\:\frac{4}{52}
factor 6x^2-384
factor\:6x^{2}-384
simplify-(2/3)/((-8/7))
simplify\:-\frac{\frac{2}{3}}{(-\frac{8}{7})}
simplify (12!)/((12-2)!)+(13!)/((13-4)!)
simplify\:\frac{12!}{(12-2)!}+\frac{13!}{(13-4)!}
1/(x-2)+1>= 0
\frac{1}{x-2}+1\ge\:0
(4-x)(x+3)(x^2-1)<= 0
(4-x)(x+3)(x^{2}-1)\le\:0
factor 6+2i
factor\:6+2i
simplify 0.85^5
simplify\:0.85^{5}
3x^2-45=0
3x^{2}-45=0
1/3 y+7>= 12
\frac{1}{3}y+7\ge\:12
simplify 8^{(-2)/3}
simplify\:8^{\frac{-2}{3}}
3^2-x-2>0
3^{2}-x-2>0
\sqrt[3]{x^3-7}<x-1
\sqrt[3]{x^{3}-7}<x-1
factor 8r^2-64r^2+r-8
factor\:8r^{2}-64r^{2}+r-8
3(x+1)^2-22=5
3(x+1)^{2}-22=5
simplify-2/3+1
simplify\:-\frac{2}{3}+1
simplify 5\sqrt[3]{32x^3y^4}-3xy\sqrt[3]{4y}
simplify\:5\sqrt[3]{32x^{3}y^{4}}-3xy\sqrt[3]{4y}
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